Question

A rock is thrown from the side of a ledge. The height (in feet), x seconds after the toss is modeled by: h (x) = -4(x-2)^2 +293 How high was the platform at the time of the launch?

Answer 1

The platform was 277 feet high at the time of the launch

Step-by-step explanation:

Given that the height is modeled by:

`h\mleft(x\mright)=-4\mleft(x-2\mright)^2+293`

To find how high the platform was at the time of the launch, we find h(0) by replacing x by 0 in the given equation.

`\begin{gathered} h(0)=-4(0-2)^2+293 \\ =-4(-2)^2+293 \\ =-4(4)+293 \\ =-16+293 \\ =277 \end{gathered}`

The platform was 277 feet high at the time of the launch