Question

How do I Express the series in sigma notation?2+5+8+11+14

Answer 1

The answer is 40 to if you were wondering

Answer 2

Step-by-step explanation

In order to represent the series in Sigma notation, we can apply the following standard form of a sequence:

`a_n=a_1+d(n-1)`

Where a_1=2, and d represent the common difference.

Computing the common difference:

5-2 = 3 8-5 = 3 11-8 = 3 14-11 = 3

Thus, the sequence is as follows:

`a_n=2+3(n-1)`

Applying the distributive property:

`a_n=2+3n-3`

Subtracting like terms:

`a_n=-1+3n`

Expressing in sigma notation:

`\sum_{i\mathop{=}1}^53n-1`