Question

Boxes are dragged along a rough surface. Calculate the acceleration of the following object below

Answer 1

Given:

The coefficient of friction, μ=0.37

The mass of the box, m=8 kg

The force applied to the box, F=32 N

To find:

The acceleration of the box.

Step-by-step explanation:

The net force acting on the box is given by,

`\begin{gathered} F_n=F-f \\ =F-mg\mu \end{gathered}`

Where g is the acceleration due to gravity.

On substituting the known values,

`\begin{gathered} F_n=32-8*9.8*0.37 \\ =2.992\text{ N} \\ \approx3\text{ N} \end{gathered}`

From Newton's second law, the net force acting on the object is given by,

`F_n=ma`

Where a is the acceleration of the object.

On substituting the known values,

`\begin{gathered} 3=8* a \\ \Rightarrow a=(3)/(8) \\ =0.375\text{ m/s}^2 \end{gathered}`

Final answer:

The acceleration of the box is 0.375 m/s²