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Factor the binomial or identify it as prime. 2z^4 - 2

User Anils
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The given binomial expression is:


2z^4-2

The common factor is 2.

Hence, we factor out 2


2z^4-2=2(z^4-1)

We then apply the diference of

Therefore, the factored answer is


\begin{gathered} 2(z^4-1) \\ =2(z^2-1)(z^2+1) \\ =2(z-1)(z+1)(z^2+1) \end{gathered}

User Yvo
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