Question

What diameter must a circular piece of stock be to mill a hexagonal shape with a side length of 2.7 in.?

Answer 1

Given:

A circular piece of stock be to mill a hexagonal shape with a side length of 2.7 ​in.

Required:

We need to find the diameter of hexagon.

Step-by-step explanation:

now use the sin function

`\begin{gathered} sin30=(1.35)/(r) \\ \\ (1)/(2)=(1.35)/(r) \\ \\ r=2.7 \end{gathered}`

so by r

`d=2r=5.4\text{ in}`

Final answer:

Diameter of hexagon is 5.4 in