1) Gathering the data
4 child buffets + 2 adult buffets = $120
3 child buffets + 3 adult buffets = $132
Let's call child buffet 'c' and adult buffet by 'a' and then set the system
4c +2a = 120
3c +3a=132
2) Solving the system by elimination method
4c +2a = 120 Multiply by -3 t
3c +3a=132 Multiply by 2
-12c -6a = -360 Adding both equations, we can eliminate one variable
6c -6a = 264
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-6c =-96
6c = 96 Divide both sides by 6
c=16
2.2 Let's plug that into one of those original equations, usually the simplest one
3c +3a = 132
3(16) +3a = 132
48 + 3a = 132 Subtract 48 from both sides
3a =132-48
3a=84 Divide both sides by 3
a=28
3) So the answers are:
How much does the buffet cost for each child and adult?
Each child: $16 Each adult: $28