Question

What are the x and y-intercepts of the line described by the equation?2x + 4y = 12.4x-intercept = y-intercept =

Answer 1

The given equation is,

`2x+4y=12.4`

X-intercept

To solve for x-intercept we will equate y = 0.

`\begin{gathered} 2x+4(0)=12.4 \\ 2x+0=12.4 \\ 2x=12.4 \\ (2x)/(2)=(12.4)/(2) \\ x=6.2 \end{gathered}`

Y-intercept

To solve for y-intercept we will equate x = 0.

`\begin{gathered} 2(0)+4y=12.4 \\ 0+4y=12.4 \\ 4y=12.4 \\ (4y)/(4)=(12.4)/(4) \\ y=3.1 \end{gathered}`

Hence,

`\begin{gathered} x-\text{intercept}=(6.2,0) \\ y-\text{intercept}=(3.1,0) \end{gathered}`