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NRKirby · Answer 1 · 2023-11-14T21:13:43+0000

The piecewise function is given as shown below:

$h(x)=\begin{cases}{-2,\text{ }if\text{ }x\leq-1} \\ {(x+1)^2,\text{ }if\text{ }-1QUESTION 1: h(-4)-4 satisfies the interval:[tex]\begin{gathered} x\leq-1 \\ -4\leq-1 \end{gathered}$

Therefore,

QUESTION 2: h(-1)

-1 satisfies the interval:

$\begin{gathered} x\leq-1 \\ -1\leq-1 \end{gathered}$

Therefore,

QUESTION 3: h(0)

0 satisfies the interval:

$\begin{gathered} -1Therefore,[tex]\begin{gathered} h(0)=(0+1)^2=1^2 \\ h(0)=1 \end{gathered}$

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