205k views
0 votes
Let h be the function defined by h(x) =2x+3. Find the range of h.

1 Answer

6 votes

\text{Range of h = (-}\infty,\text{ }\infty)

Step-by-step explanation:

h(x) =2x+3

let h(x) = y

y = 2x + 3

Solve by interchanging x an y:

x = 2y + 3

Make y the subject of formula:


\begin{gathered} 2y\text{ = x-3} \\ y\text{ = }(x-3)/(2) \end{gathered}

Fromthe above, x can take on the value of any number. This is because no real number will make x undefined.

The range of h(x) =2x+3 will span from negative infinity to positive infinity.


\text{Range of h = (-}\infty,\text{ }\infty)

User Zygimantus
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories