Given:
The boy pulls his sister by the force
![F=57\text{ N}](https://img.qammunity.org/2023/formulas/physics/college/rmvn68jy9sdptx6hj811mtlur175jw798s.png)
The force is at an angle of
![\theta=30\degree](https://img.qammunity.org/2023/formulas/physics/college/n5endhjvj2g26obo6hrbtfgyrjgxpannz0.png)
The displacement is,
![d=31\text{ m}](https://img.qammunity.org/2023/formulas/physics/college/wuki1cbppxiigvrqtae4kxs63fui4xyon7.png)
To find:
The work by the boy
Step-by-step explanation:
The component of the force along the displacement is,
![\begin{gathered} Fcos\theta=57* cos30\degree \\ =49.4\text{ N} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/plw6q5jll3g3w2zhi4ex5xlhzqxd12bndl.png)
The work done by the boy in pulling his sister is,
![\begin{gathered} W=Fcos\theta* d \\ =49.4*31 \\ =1531.4\text{ J} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/w2aq0ombpagf9m5h42n39785rju4kokvlb.png)
Hence, the work is 1531.4 J.