To evaluate a function with a specific value in the domain you susbtitute in the equation of the function the independient variable (x) for the value in domain.
![y=2\cdot3^x](https://img.qammunity.org/2023/formulas/mathematics/high-school/3z2u6wt0ehp8isv8bi6gj7ekc87l03t78j.png)
For x = -1 (a number n powered to a negative number (m) n^-m is equal to 1/n^m
![y=2\cdot3^(-1)=2\cdot(1)/(3)=(2)/(3)\approx0.66](https://img.qammunity.org/2023/formulas/mathematics/high-school/unnhb78fueydl12gplbn4bj3pb4zetr7fu.png)
For x=0 (any number powered to 0 is equal to 1)
![y=2\cdot3^0=2\cdot1=2](https://img.qammunity.org/2023/formulas/mathematics/high-school/jedaf1uwux0vtsvodla7qimpyjvel32g6n.png)
For x = 1
![y=2\cdot3^1=2\cdot3=6](https://img.qammunity.org/2023/formulas/mathematics/high-school/d6hocxlfjz9totf46wr3qny9pobpkryecq.png)
For x = 2
![y=2\cdot3^2=2\cdot9=18](https://img.qammunity.org/2023/formulas/mathematics/high-school/qd0xice91yzylgjnj6n2rijcwx8v7kgq7j.png)
Then, as you can see as the values of the domain increase, the values of the function increase