Question

A graduated cylinder was filled with water to the 11.2 mL mark and weighed on a balance. Its mass was 25.92 g. An object made of silver was placed in the cylinder and completely submerged in the water. The water level rose to 15.6 mL. When reweighed, the cylinder, water, and silver object had a total mass of 72.12 g. Calculate the density of silver in g/cm3.Express your answer to two significant figures.

Answer 1

Explanation;

Here, we want to get the density of silver

We start by getting the mass of the silver

That would be the difference between the total mass after insertion of silver and before

We have this as:'

`\text{ 72.12 g - 25.92 g = 46.20 g}`

Now, we want to get the volume of the silver which is equal to the volume of water displaced

Mathematically, we have that as:

`\text{ 15.6 mL - 11.2 mL = 4.4 mL}`

Mathematically, we know that mL is the same as cm^3, so the value of the volume remains the same

Finally, we can get the density by dividing the mass of the silver by the volume of water displaced

Mathematically, we have that as:

`(46.20)/(4.4)=10.5g/cm^3`