Question

line p contains point (6 ,- 5 and is perpendicular to line q the equation for line q is y=3x+5 the slope of line q is 3. the slope of line p is -1/3.) Use the point given for line p and the slope you found to write an equation for line p in point-slope form

Answer 1

We are told that the slope of line p = -1/3

line p can be written as:

y = -1/3x + c

We will substitute the point (6,-5) into the equation to find c.

-5 = -1/3(6) + c

-3 = c

Line p in point slope form is therefore:

y = -1/3x - 3