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Question 81 pt 91 0 DetailsA die is rolled twice. What is the probability that a(n) 1 is rolled on the first roll and an even number on thesecond roll?The probability of rolling a(n) 1 on the first roll and an even number on the second roll is

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Given:

A die is rolled twice.

To find:

What is the probability that 1 is rolled on the first roll and an even number on the second roll?

Step-by-step explanation:


Probability\text{ of event= }\frac{favorable\text{ outcome}}{Total\text{ outcome}}

Solution:

A die is roll twice.

Each roll of the dice is an independent event. The probability of a 1 on one roll is 1/6 and the probability of an even number on the second roll is 3/6=1/2. Since, each roll is an independent event, the probability of a 1 on one roll and an even number on the second roll is


(1)/(6)*(1)/(2)=(1)/(12)

Hence, these are the required probabilities.

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