1 Answer

Sisi · Answer 1 · 2023-08-21T04:53:48+0000

Given the system of equations:

$\begin{cases}3x-4y=20 \\ 2x+4y=0\end{cases}$

Add up both equations:

$\begin{gathered} \begin{cases}3x-4y=20 \\ 2x+4y=0\end{cases}\rightarrow3x+2x-4y+4y=20+0 \\ \rightarrow5x=20 \end{gathered}$

Solve for x,

$\begin{gathered} 5x=20\rightarrow x=(20)/(5) \\ \Rightarrow x=4 \end{gathered}$

Plug the value of x in equation 2 and solve for y,

$\begin{gathered} 2x+4y=0\rightarrow2(4)+4y=0\rightarrow8+4y=0 \\ \rightarrow4y=-8\rightarrow y=-(8)/(4) \\ \Rightarrow y=-2 \end{gathered}$

Thereby,

$\begin{gathered} x=4 \\ y=-2 \end{gathered}$

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