Question

How many grams are in 87.37e26 atoms of (NH4)2SO4?

Answer 1

1917149.087 grams of (NH₄)₂SO₄ are in 87.37 x 10²⁶ atoms of (NH₄)₂SO₄.

Step-by-step explanation

Given that:

The number of atoms of (NH₄)₂SO₄ = 87.37 x 10²⁶ atoms

What to find:

To find the grams of (NH₄)₂SO₄ in 87.37 x 10²⁶ atoms of (NH₄)₂SO₄.

Step-by-step solution:

Step 1: Convert 87.37 x 10²⁶ atoms of(NH₄)₂SO₄ to moles.

Conversion factor: One mole of a substance will contain 6.022 × 10²³ atoms of that substance

`\begin{gathered} 1\text{ }mole\left(NH₄\right)₂SO₄=6.022×10²³\text{ }atoms \\ \\ x=87.37×10²⁶\text{ }atoms \\ \\ x=\frac{87.37×10²⁶\text{ }atoms}{6.022×10²³\text{ }atoms}*1\text{ }mole\left(NH₄\right)₂SO₄ \\ \\ x=14508.46895\text{ }mol\left(NH₄\right)₂SO₄ \end{gathered}`

Step 2: Convert 14508.46895 moles of (NH₄)₂SO₄ to grams.

Using the molar mass of (NH₄)₂SO₄ = 132.14 g/mol and the mole formula below, the grams of (NH₄)₂SO₄ can be determined as follows:

`\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Mass=Moles* Molar\text{ }mass \\ \\ Mass\text{ }of\text{ }\left(NH₄\right)₂SO₄=14508.46895\text{ }mol*132.14\text{ }g\text{/}mol \\ \\ Mass\text{ }of\text{ }\left(NH₄\right)₂SO₄=1917149.087\text{ }g \end{gathered}`

Therefore, 1917149.087 grams of (NH₄)₂SO₄ are in 87.37 x 10²⁶ atoms of (NH₄)₂SO₄.