Question

Calculate the volume of the following gas sample at STP. 22.2 mol Cl2

Answer 1

In the most used STP conditions, the volume occupied by 1 mol of a gas is 22.4 L.

That is, 1 mol to 22.4 L. Since we know we have 22.2 mol of a gas in STP, we can use the rule of three to find its volume:

1 mol --- 22.4 L

22.2 mol --- V

`\begin{gathered} (1mol)/(22.2mol)=(22.4L)/(V) \\ V=22.2mol*(22.4L)/(1mol)=497.28\approx497L \end{gathered}`

So, the volume is approximately 497 L.