Question

A scientist expected that a particular chemicalreaction would produce 7.40 micromoles (umol) ofcarbon dioxide. The amount of carbon dioxideproduced was 75.0% of the scientist's expectation.How much carbon dioxide, in mol, was produced?

Answer 1

Data:

• Product expectation: 7.40 umol

,

• Actual production: 75% of the expected.

Procedure

First, we have to get the proportion of 75 ad follows:

`(75\%)/(100\%)=0.75`

Then, we have to multiply that proportion to the product expectation:

`7.40*0.75=5.55`

5.55 umol of carbon dioxide were produced. However, the problem is asking in mol, thus we have to make the following conversion:

`5.55umol*\frac{1\text{mol}}{1000000umol}=0.00000555\text{mol}=5.55*10^(-6)mol`

Answer: 0.00000555