Answer:
![\begin{gathered} (f(x))/(g(x))=\frac{5x\cdot\sqrt[]{x-1}}{x-1} \\ \text{Domain(f/g)(x)}=x>1\text{ or (1,}\infty) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/70gesldquja8k106o5fwximomxqe7q56xs.png)
Step by step explanation:
We have to find the division of the functions:
![\begin{gathered} f(x)=5x \\ g(x)=\sqrt[]{x-1} \\ ((f)/(g))(x)=(f(x))/(g(x)) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7eoh42delya08mgxntvoesgz778e4h5l27.png)
Then, by the division we get:
![(f(x))/(g(x))=\frac{5x}{\sqrt[]{x-1}}](https://img.qammunity.org/2023/formulas/mathematics/college/2kuhc5xpysa2jdr3mv8stnaykr7e64152k.png)
To solve the division, we have to multiply by the conjugated:
![\begin{gathered} (f(x))/(g(x))=\frac{5x\cdot\sqrt[]{x-1}}{\sqrt[]{x-1}\cdot\sqrt[]{x-1}} \\ (f(x))/(g(x))=\frac{5x\cdot\sqrt[]{x-1}}{x-1} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bs5qel8fitjzgexssk4unycf78fgyudrqi.png)
Since the function can only take a number greater than 1 because we need a number different from zero on the denominator and no negative values on the roots.