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The solution for a(bx+7)=c is x=10. Give possible values for a,b and c

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Given the equation;


\begin{gathered} a(bx+7)=c \\ Where; \\ x=10 \end{gathered}

We will begin by inserting the value of x into the left hand side of the equation as follows;


\begin{gathered} a(b(10)+7)=c \\ a(10b+7)=c \\ \text{If } \\ a=1,\text{ then;} \\ 10b+7=c \\ S\text{imilarly, if} \\ b=2,\text{ then} \\ 10(2)+7=c \\ 20+7=c \\ 27=c \end{gathered}

ANSWER:

Therefore, the possible values for a, b, and c are;


\begin{gathered} a=1 \\ b=2 \\ c=27 \end{gathered}

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