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Through (-2,3) and (0,2 )

1 Answer

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The slope of the line that passes through the points (x1, y1) is computed as follows:


m=(y_2-y_1)/(x_2-x_1)

Given that the line passes through (-2,3) and (0,2)​, then its slope is:


m=(2-3)/(0-(-2))=-(1)/(2)

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept

Replacing the point (0, 2) and m = -1/2 into the general equation, we get:

2 = -1/2(0) + b

2 = b

Then, the equation of the line is:

y = -1/2x + 2

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