Hello there. To solve this question, we have to remember some properties about histograms.
Given the following data, we want to determine:
649896
937097
746763
718057
807743
677852
659253
658762
654364
666450
a) The number of bins in the histogram
For this, we use the following formula:
![\text{bins}=1+\lceil\log_2(n)\rceil](https://img.qammunity.org/2023/formulas/mathematics/college/6skjg3pbtk58pw7sk4fhquszbwc7s4ak86.png)
In this case, we have 30 values, hence
![\text{b}\imaginaryI\text{ns}=1+\operatorname{\lceil}\operatorname{\log}_2(30)\operatorname{\rceil}\approx1+5=6]()
b) What size should your intervals be?
For this, we want to determine the width of a bin.
Using the following formula:
![\text{ bin width }=(\max(x)-\min(x))/(bins)](https://img.qammunity.org/2023/formulas/mathematics/college/o6yyspz1qtpnhh6e5wdz9q84n2odhe12pg.png)
Where max(x) represents the maximum value in the data set, min(x) is the minimum value and bins is the number we found on a).
We get that max(x) = 98 and min(x) = 43, hence
![\text{ bin width }=(98-43)/(6)=(55)/(6)\approx9.16](https://img.qammunity.org/2023/formulas/mathematics/college/9y8ymwref0p6bqe6rhyg2nx64sgkg4fk7e.png)
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