Question

Give the equation for a circle with the given center and radius.Center at (-1, 3), radius = 4A. (x+3)2+(y−1)2=4B. (x−1)2+(y+3)2=16C. (x+1)2+(y−3)2=16D. (x−3)2+(y+1)2=4Don't need explanation just answer!

Answer 1

C. (x + 1)² + (y − 3)² =16

Explanation:

We have that the equation of the circle has the following structure:

`\begin{gathered} \left(x−a\right)^2+\left(y−b\right)^2=r^2 \\ \\ \text{ Where \lparen a, b\rparen is the center and r is the radius.} \end{gathered}`

We replace the center and the radius and we are left with the following:

`\begin{gathered} \left(x-(-1)\right)^2+\left(y-3\right)^2=4^2 \\ \\ \left(x+1\right)^2+\left(y-3\right)^2=16 \end{gathered}`

This means that the correct answer is C. (x + 1)² + (y − 3)² =16