hello
to solve this problem, we have to use the formula of volume of a rectangle
but in this case, the value of the volume given is just 3/4 of the tank
if 3/4 of the tank is 14.4L, a full tank would be?
the volume of the full tank would be 19.2L
let's use this information and solve for the height
but before we do that, we have to have a uniform S.I unit
convert the volume in L to cm^3
![\begin{gathered} 1l=1000\operatorname{cm}^3 \\ 19.2L=x \\ x=(19.2*1000)/(1) \\ x=19200\operatorname{cm}^3 \end{gathered}]()
we can now solve for the height of the rectangle
![\begin{gathered} v=l* w* h \\ v=19200\operatorname{cm}^3 \\ l=40\operatorname{cm} \\ w=20\operatorname{cm} \\ 19200=40*20* h \\ 19200=800h \\ \text{divide both sides by coefficient of h} \\ (19200)/(800)=(800h)/(800) \\ h=24\operatorname{cm} \end{gathered}]()
from the calculations above, the height of the rectangle is 24cm