Question

What is the change of velocity of a 2000 kg car that is accelerated by a constant force of 4000 N acting for 10.0 s?20.0 m/s50.0 m/s5.0 m/s10.0 m/s

Answer 1

To solve this question we can use the below equation,

`\begin{gathered} F=(\Delta P)/(\Delta t) \\ Where, \\ \Delta P=Change\text{ }in\text{ }momentum \\ \Delta t=Change\text{ }in\text{ }time \end{gathered}`
`\begin{gathered} F=(\Delta P)/(\Delta t)=(m\Delta V)/(\Delta t) \\ Here,\text{ }\Delta v=Change\text{ }in\text{ }velocity \\ For\text{ }this\text{ }question, \\ F=4000N \\ m=2000kg \\ \Delta t=10\text{ }s \\ So, \\ \Delta V=(F*\Delta t)/(m)=(4000*10)/(2000)=20\text{ m/s} \end{gathered}`

So The change in velocity = 20 m/s

So 1st option is correct option.