We have a direct variation between x and y.
We can write this as:
![y=k\cdot x](https://img.qammunity.org/2023/formulas/mathematics/college/a0r8mfu5ejnpo5kqd0vablwmcl6k945tnc.png)
where k is a constant.
Knowing one point of the relation, like (-2,-8) we can calculate k as:
![k=(y)/(x)=(-8)/(-2)=4](https://img.qammunity.org/2023/formulas/mathematics/college/8p0yjatek1j3rhc4mhvpenanxpw9a2w52q.png)
Then, if we have the point (x,36), we have to calculate the value of x.
As we know that y = 36 and k = 4, we can find x as:
![\begin{gathered} y=k\cdot x \\ x=(y)/(k)=(36)/(4)=9 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8kx33uq2saetjshv71w1pba0pofidmqr9z.png)
Answer: the missing value is x = 9