Question

You have found the following ages (in years) of 5 gorillas. Those gorillas were randomly selected from the 29 gorillas at your local zoo:8, 4, 14, 16, 8,Based on your sample, what is the average age of the gorillas? What is the standard deviation? Round your answers to the nearest tenth.average age_______standard deviation_________

Answer 1

Explanation:

dude I got it wrong bc I followed the comment before. The first answer is right

Answer 2

Average age 10

Standard deviation 4.9

Explanation:

To calculate average age of the gorillas:

`average=(\sum^n_i)/(n)`

Replacing:

`\begin{gathered} average=(8+4+14+16+8)/(5) \\ average=(50)/(5) \\ average=10 \end{gathered}`

The average age of the gorillas is 10

The formula for standard deviation is:

`s^2=(1)/(n-1)\cdot\sum ^n_i(x_i-\bar{x})^2`

Replacing:

`\begin{gathered} s^2=(1)/(5-1)\cdot\mleft\lbrace(8-10)^2+(4-10)^2+(14-10)^2+(16-10)^2+(8-10)^2\mright\rbrace^{} \\ s^2=(1)/(4)\cdot(4+36+16+36+4) \\ s^2=(96)/(4) \\ s=\sqrt[]{24} \\ s=4.9 \end{gathered}`

The standard deviation of gorillas is 4.9