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When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 3 kg, the acceleration of the object is 10 /ms2. If the same force acts upon another object whose mass is 2 kg, what is this object's acceleration?

User Furi
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Step-by-step explanation

From the question, we can see that the acceleration of the object varies inversely with the mass when a certain constant force acts on the object. We can express this as;


a=(f)/(m)

Therefore, when the mass is 3kg, the acceleration of the object is 10 /ms2.


\begin{gathered} 10=(f)/(3) \\ f=10*3 \\ f=30ms^(-2) \end{gathered}

Therefore, if the same force acts upon another object whose mass is 2 kg, the object's acceleration becomes.


\begin{gathered} a=(30)/(2) \\ a=15ms^(-2) \end{gathered}

Answer: 15 meters per seconds square.

User Joe Bathelt
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