It is given that $2000 was placed in an account that pays 16% interest compounded each year.
The Compound Interest Formula is given as:
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/39foo2gerf9tf1ffk32zwshrn339mz02kv.png)
Where P is the amount placed in the account, r is the interest rate, n is the number of times the interest is compounded in a year, and t is the time passed in years.
(a) It is required to find the amount after 1 year.
Substitute P=2000, r=16%=0.16, n=1, and t=1 into the equation:
![\begin{gathered} A=2000(1+(0.16)/(1))^(1(1)) \\ \Rightarrow A=2000(1+0.16)^1=2000(1.16)=\$2320 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/56fmvcjd7g375ylh8q26b7vd84cf20arxn.png)
(b) It is required to find the amount after 2 years.
Substitute P=2000, r=16%=0.16, n=1, and t=2 into the equation:
![\begin{gathered} A=2000(1+(0.16)/(1))^(1(2)) \\ \Rightarrow A=2000(1+0.16)^2=2000(1.16)^2=2000(1.3456)=\$2691.2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x09mmks55p8tefym1d5htg1fi5cgxxoqjx.png)
Answers:
(a) $2320
(b) $2691.2