. Solve for y a. y² = 35 b. y³ = 1000

asked Dec 14, 2023 118k views

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. Solve for y
a. y² = 35
b. y³ = 1000

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2 votes

a.
y^(2) = 35 - > y =+- √(35)
b.
$y^(3) = 1000 - > \sqrt[3]{1000} = 10$

(+ - means either minus 35 or 35)

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6 votes

Part a

$y^2=35 \implies y=\pm √(35)$

Part b

$y^3=1000 \implies y=\sqrt[3]{1000}=10$

Bodger answered Dec 21, 2023

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