Question

Write both solutions3x² + 2x - 8 = 0

Answer 1

Given:

`3x^2+2x-8=0`

Required:

To find the solution of the given equation.

Step-by-step explanation:

Consider

`3x^2+2x-8=0`
`x=(-b\pm√(b^2-4ac))/(2a)`
`\begin{gathered} =(-2\pm√(2^2-4(3)(-8)))/(2(3)) \\ \\ =(-2\pm√(4+96))/(6) \\ \\ =(-2\pm10)/(6) \end{gathered}`

Now

`\begin{gathered} x=(-2+10)/(6) \\ \\ x=(8)/(6) \\ \\ x=(4)/(3) \end{gathered}`

And

`\begin{gathered} x=(-2-10)/(6) \\ \\ x=(-12)/(6) \\ \\ x=-2 \end{gathered}`

Final Answer:

`x=-2,(4)/(3)`