Given line parallel to x=5 and passes through point (-6,13)
So to find equation of line
Slope of line joining x=5 and the parallel to it will be same m=∞
So the equation of line having m=1/0=∞ and passing through (-6,13) will be
y=m .x+C
![13=(1)/(0)*-6+C](https://img.qammunity.org/2023/formulas/mathematics/college/3uwetsuae5ht38jxwcx234wou9softdha9.png)
![C=6](https://img.qammunity.org/2023/formulas/mathematics/college/wz7rajwjtet5nyh5mxjgctoep7k61fswlh.png)
On substituting the value in C we get
![y=(1)/(0)x+6](https://img.qammunity.org/2023/formulas/mathematics/college/6lbzkmugca1d352uzmamonsmjiz83yvie2.png)
Hence this is the equation of required line is x=6.