Question

If the point is on the unit circle what is X

Answer 1

The question can be represented by:

where

`y=\frac{\sqrt[]{3}}{2}`

Note that the Hypotenuse is 1 because a unit circle has a radius of 1.

Considering the triangle from the diagram above, we can find x using the Pythagorean Theorem:

`\begin{gathered} 1^2=x^2+y^2 \\ 1=x^2+(\frac{\sqrt[]{3}}{2})^2 \\ 1=x^2+(3)/(4) \end{gathered}`

Solving for x, we have

`\begin{gathered} x^2=1-(3)/(4) \\ x^2=(1)/(4) \\ x=\sqrt[]{(1)/(4)} \\ x=(1)/(2) \end{gathered}`

The value of x is 1/2.