Question

How many moles of NH3 are formed from 61.3 g of N2H4?

Answer 1

1) Balance the chemical equation

`3N_2H_4(l)\rightarrow4NH_3(g)+N_2(g)`

2) Convert grams of N2H4 into moles of N2H4.

The molar mass of N2H4 is 32.04516 g/mol

`\text{mol }N_2H_4=61.3gN_2H_4\cdot(1molN_2H_4)/(32.04516gN_2H_4)=1.912925molN_2H_4`

3) Moles of NH3 produced from 1.912925 mol N2H4

3 N2H4: 4 NH3

`\text{mol NH}_3=1.912925molN_2H_4\cdot(4molNH_3)/(3molN_2H_4)=2.55057molNH_3`

61.3 g N2H4 can produce 2.55 mol NH3.

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