Question

Congruence - SSS theoremIll send a picture of the question

Answer 1

From the figure,

We need to prove that,

`\Delta\text{MNO}\cong\Delta\text{PQR}`

By SSS theorem,

`\begin{gathered} MN\cong PQ(\text{Given)} \\ NO\cong QR(\text{Given)} \end{gathered}`

So, the third side must be,

`MO\cong PR`

Hence, the correct option is D.