Question

POSSIBLE POINTS 7.69 An architect's blueprint for a new house shows the pool being 2 inches wide. If the scale used to create the blueprint is 0.25 in. = 3 ft., what is the actual width of the pool?

Answer 1

`\begin{gathered} \text{Let w represents the actual width} \\ \text{ scale is 0.25in = 3 ft} \\ \text{ }\frac{0.25in}{3\text{ ft}}\text{ = }(2)/(w) \\ \\ 0.25w=\text{ 2 x 3} \\ 0.25w=6 \\ w=(6)/(0.25) \\ w=24 \end{gathered}`

The actual width of the pool is 24 ft