Question

Question 10 of 10 Select the two values of x that are roots of this equation. x² + 2x - 4=0 . O A. x= -1- 5 B. X=-1+2.5 C. X=-1-2-15 D. X=-1+ 5 SUBMIT

Answer 1

Given

`x^2+2x-4=0`

Using the quadratic formula

`\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Given parameters} \\ a=1 \\ b=2 \\ c=-4 \end{gathered}`

Subsitute the given parameters into the formula

`\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \\ x=\frac{-2\pm\sqrt[]{2^2^{}-4*1*-4}}{2*1} \\ \\ x=\frac{-2\pm\sqrt[]{2^2+16}}{2} \\ \\ x=\frac{-2\pm\sqrt[]{4^{}+16}}{2} \\ x=\frac{-2\pm\sqrt[]{20}}{2} \\ \\ x=\frac{-2\pm\sqrt[]{4*5}}{2} \\ x=\frac{-2\pm2\sqrt[]{5}}{2} \\ x=-1\pm\sqrt[]{5} \end{gathered}`

The final answer

Option A and Option D

`\begin{gathered} x=-1-\sqrt[]{5} \\ \text{and} \\ x=-1+\sqrt[]{5} \end{gathered}`

The summary