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How many moles of H2O areequivalent to 97.3 grams ofH2O?(H = 1.008 g/mol, O = 16.00 g/mol)[?] molEnter

How many moles of H2O areequivalent to 97.3 grams ofH2O?(H = 1.008 g/mol, O = 16.00 g-example-1

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Before we find the number of moles of H₂O that we have in the 97.3 g sample of it, we have to find the molar mass of H₂O. We are given the molar mass of H and O.

H = 1.008 g/mol O = 16.00 g/mol

One molecule of H₂O has 2 atoms of H and 1 atom of O. We can calculate its molar mass like this:

molar mass of H₂O = 2 * molar mass of H + 1 * molar mass of O

molar mass of H₂O = 2 * 1.008 g/mol + 1 * 16.00 g/mol

molar mass of H₂O = 18.016 g/mol

Now that we know that 1 mol of H₂O has a mass of 18.016 g, we can find the number of moles of H₂O that there are in 97.3 g of it.

number of moles of H₂O = mass of H₂O/molar mass of H₂O

number of moles of H₂O = 97.3 g/(18.016 g/mol)

number of moles of H₂O = 5.40 moles

Answer: there are 5.40 moles of water in 97.3 g of it.