Question

Graph y = (1/2)|x + 2| – 1 using transformations

Answer 1

First let's start with the graph of y = x:

Then, let's apply the "absolute value" operator: y = |x|

Then, we have an horizontal translation of 2 units to the left: y = |x + 2|:

Then, a vertical stretch by a factor of 1/2: y = (1/2)|x + 2|:

Finally, a vertical translation of 1 unit down: y = (1/2)|x + 2| - 1: