f(z) =z² - 3+2i
For the firs ouput subsitute z =0 in the above
f(0) = (0)² - 3 + 2i = -3 + 2i
For the second output, substitute z=-3 + 2i into the function
f(-3+2i) = (-3+2i)² - 3 + 2i
=(-3+2i)(-3+2i) - 3 + 2i
= 9 -6i - 6i - 4 - 3 + 2i
= 9 -12i - 7 + 2i
= 2 - 10i
For the third output, substitute 2-10i into the function
f(2-10i) = (2-10i)² - 3 + 2i
= (2-10i)(2-10i) - 3 + 2i