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You are choosing two cards, replacing the first card in the deck after it has been drawn. What is the probability you choose two consecutive fours?

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With replacement:


P=(4)/(52)\cdot(4)/(52)=(16)/(2704)=(1)/(169)

there are four 4s in the 52-card deck -> 4/52

Since you return that card into the deck, the probability of getting two consecutive 4s will be (4/52)*(4/52)

User Geert Van Laethem
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