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Find the surface area of the tunnel created inside the block.

Find the surface area of the tunnel created inside the block.-example-1
User Wruckie
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The surface area of the tunnel passing through the block is simply the curved surface area of the cylindrical shape.

The Surface Area is given by


A=2\pi rh

where the following are given from the question:


\begin{gathered} r=(4)/(2)=2ft \\ h=4ft \end{gathered}

Substituting these values:


\begin{gathered} A=2*\pi*2*4 \\ A=50.27 \end{gathered}

Therefore, the surface area of the tunnel created inside the block is 50.27 ft² (50.27 square feet)

User Bharat Gupta
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