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Find the discriminant value of 25q^2-40q+16=0
Please show work!!!

User TotalAMD
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The discriminant value of a quadratic equation is b^2 - 4ac.

We can see here, in this quadratic equation, 25 is a, 40 is b and 16 is c (as in ax^2 + bx + c)

Applying it to the discriminant value = 40^2 - 4 x 25 x 16 = 1600 - 1600 = 0.
(And since the discriminant value is 0, the quadratic function has 1 repeated real root.)

User Nermik
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