ANSWER
The slope of the equation of the line is y =x - 2
Explanation:
What to find? The equation that passes through the lines given
Given parameters
Line A = (-1, -3)
Line B = (1, -1)
The first thing is to find the slope

According to the point given
let
x1 = -1
y1 = -3
x2 = 1
y2 = -1
Substitute the above data into the slope formula

The slope of the two lines in 1
Recall that, the slope-intercept equation of a line is given as

Where
m = slope of the line
b = intercept of the y-axis
![\begin{gathered} (y\text{ - y1) = m(x - x1)} \\ m\text{ = 1} \\ \lbrack(y\text{ - (-3)\rbrack= 1\lbrack(x - (-1)\rbrack} \\ \text{open the parentheses} \\ y\text{ + 3 = 1(x + 1)} \\ y\text{ + 3 = x + 1} \\ \text{Substract 3 from both sides} \\ y\text{ + 3 - 3 = x + 1 - 3} \\ y\text{ = x + 1 -}3 \\ y\text{ = x - 2} \end{gathered}]()
Hence, the equation that passes through the line is y = x - 2