Question

Find the equation of the line that passes through the points (-1,-3) and (1,-1) Detailed step by step

Answer 1

The slope of the equation of the line is y =x - 2

Explanation:

What to find? The equation that passes through the lines given

Given parameters

Line A = (-1, -3)

Line B = (1, -1)

The first thing is to find the slope

`\begin{gathered} \text{slope = }\frac{rise}{\text{run}} \\ \text{rise = y}_2-y_1 \\ \text{run = x}_2-x_1 \\ \text{Slope = }\frac{y_2-y_1}{x_{2\text{ }}-x_1} \end{gathered}`

According to the point given

let

x1 = -1

y1 = -3

x2 = 1

y2 = -1

Substitute the above data into the slope formula

`\begin{gathered} \text{Slope = }\frac{-1\text{ -(-3)}}{1\text{ -(-1)}} \\ \text{slope }=\text{ }\frac{-1\text{ + 3}}{1\text{ + 1}} \\ \text{slope = }(2)/(2) \\ \text{slope = 1} \end{gathered}`

The slope of the two lines in 1

Recall that, the slope-intercept equation of a line is given as

`y\text{ = mx + b}`

Where

m = slope of the line

b = intercept of the y-axis

Hence, the equation that passes through the line is y = x - 2