In order to answer this question, we need to find the volume of one cubic box and the volumeof the storage bin.
The volume of the cubic box is given by

which gives

On the other hand, the volume of the storage bin is given by

but we need to convert first the mixed fraction form into a simple fraction form, that is

then, its volume is

Now, we need to compare our last volume with the volume of the cubic box, that is,

this means that Alan can keep 80 cubic boxes into the storage bin