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What is the quotient of {15p^5-9p^3+6p^2}÷{3p^2}?

User Dbaugh
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4.4k points

1 Answer

4 votes

To solve

First step

Divide 15p⁵ by 3p²

When you divide you will have 5p³

Write it at the top of the root

Next step 2

Multiply 3p² by 5p³ , the result is 15p⁵

Write this inside the root sign under 15p⁵

Next step 3

subtract

Next step 4

Take down -9p³

Next step 5

Divide -9p³ by 3p²

The result is -3p

Write the result (-3p) on the root sign

Next step 6

Multiply -3p² by - 3p

The result is -9p³

Write the result in the root sign under -9p³

Next step 7

subtract -9p³ from -9p³ , the result is zero(0)

Next step 8

Take down 6p²

Next step 9

Divide 6p² by 3p²

The result is 2

Write the result at the top of the root sign

Next step 10

Multiply 3p² by 2, the result is 6p²

Write the result in the root sign under 6p²

Next step 11

Subtract 6p² from 6p², the result is 0

Hence the quotient is;


5p^3-3p+\text{ 2}

What is the quotient of {15p^5-9p^3+6p^2}÷{3p^2}?-example-1
User Fanruten
by
5.2k points