In order to calculate the true speed and direction of the ball, let's calculate the horizontal and vertical directions of the ball speed (b) and of the wind speed (w):
![\begin{gathered} b_x=b\cdot\cos(\theta)\\ \\ b_x=1.4\cdot\cos(130°)\\ \\ b_x=1.4\cdot(-0.6428)\\ \\ b_x=-0.900\text{ m/s}\\ \\ \\ \\ b_y=b\cdot\sin(\theta)\\ \\ b_y=1.4\operatorname{\cdot}\sin(130°)\\ \\ b_y=1.4\operatorname{\cdot}0.766\\ \\ b_y=1.072\text{ m/s} \end{gathered}]()
![\begin{gathered} w_x=w\cdot\cos(\theta)\\ \\ w_x=1.1\operatorname{\cdot}\cos(50°)\\ \\ w_x=1.1\operatorname{\cdot}0.6428\\ \\ w_x=0.707\text{ m/s}\\ \\ \\ \\ w_y=w\operatorname{\cdot}\sin(\theta)\\ \\ w_y=1.1\operatorname{\cdot}\sin(50°)\\ \\ w_y=1.1\operatorname{\cdot}0.766\\ \\ w_y=0.843\text{ m/s} \end{gathered}]()
Now, let's add the horizontal components together and the vertical components together:
To calculate the magnitude and direction of this resultant speed, we can use the formulas below:
Therefore the correct option is the second one.