Question

F=9/5C + 32 solve for C

Answer 1

`F=(9)/(5)C+32`

To solve for C let us do these steps

1. Put the term of C on one side and the other terms on the other side

Subtract 32 from both sides to move the term 32 to the other side

`\begin{gathered} F-32=(9)/(5)C+32-32 \\ F-32=(9)/(5)C \end{gathered}`

2. Make the coefficient of C = 1

Divide both sides by 9/5

`\begin{gathered} (F-32)/((9)/(5))=((9)/(5)C)/((9)/(5)) \\ (5)/(9)(F-32)=C \\ C=(5)/(9)(F-32) \end{gathered}`

You can Multiply the bracket (F- 32) by 5/9

`C=(5)/(9)F-(160)/(9)`