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In the triangle shown we can find the angle as follows.A153936(a) = sin-X(b) 0 - cos(C) 0 = tan-10

In the triangle shown we can find the angle as follows.A153936(a) = sin-X(b) 0 - cos-example-1
User Nevil
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We need to calculate the three trigonometrics relations on the right triangle. They are as follow:


\begin{gathered} \sin \theta=(36)/(39)=0.92 \\ \cos \theta=(15)/(39)=0.38 \\ \tan \theta=(36)/(15)=2.4 \end{gathered}

We need to use this values on each option. The "sin^-1" is the inverse of the sine, the "cos^-1" is the inverse of the cosine and the "tan^-1" is the inverse of the tangent. If we use these values on the functions we will find the value of theta.


\sin ^(-1)0.92=\text{ 66.93}

The angle is equal to 66.93 degrees

User David Macek
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