Question

:) A mechanic took 8 hours totune up 6 fuel injected engines.How many engines can he tuneup in 24 hours?

Answer 1

Input data

A mechanic took 8 hours

Tune up 6 fuel

Procedure

ratio

`r=\frac{6\text{ engines}}{8\text{ hours}}=0.75\text{ eng/h}`

Now for 24h

`\begin{gathered} e=24\cdot0.75\text{ eng/h} \\ e=18\text{ engines} \end{gathered}`